5x(x+2)=2(x^2-1)+3(x^2+4)

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Solution for 5x(x+2)=2(x^2-1)+3(x^2+4) equation: 


Simplifying
5x(x + 2) = 2(x2 + -1) + 3(x2 + 4)

Reorder the terms:
5x(2 + x) = 2(x2 + -1) + 3(x2 + 4)
(2 * 5x + x * 5x) = 2(x2 + -1) + 3(x2 + 4)
(10x + 5x2) = 2(x2 + -1) + 3(x2 + 4)

Reorder the terms:
10x + 5x2 = 2(-1 + x2) + 3(x2 + 4)
10x + 5x2 = (-1 * 2 + x2 * 2) + 3(x2 + 4)
10x + 5x2 = (-2 + 2x2) + 3(x2 + 4)

Reorder the terms:
10x + 5x2 = -2 + 2x2 + 3(4 + x2)
10x + 5x2 = -2 + 2x2 + (4 * 3 + x2 * 3)
10x + 5x2 = -2 + 2x2 + (12 + 3x2)

Reorder the terms:
10x + 5x2 = -2 + 12 + 2x2 + 3x2

Combine like terms: -2 + 12 = 10
10x + 5x2 = 10 + 2x2 + 3x2

Combine like terms: 2x2 + 3x2 = 5x2
10x + 5x2 = 10 + 5x2

Add '-5x2' to each side of the equation.
10x + 5x2 + -5x2 = 10 + 5x2 + -5x2

Combine like terms: 5x2 + -5x2 = 0
10x + 0 = 10 + 5x2 + -5x2
10x = 10 + 5x2 + -5x2

Combine like terms: 5x2 + -5x2 = 0
10x = 10 + 0
10x = 10

Solving
10x = 10

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '10'.
x = 1

Simplifying
x = 1

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